## Article #8

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## 直列アイテム

ここで、信頼度を故障率で表す(4.2)を用いれば、(8.2)となります。 $R_{item}(t)=e^{-\lambda_{item}t}=e^{-\lambda_1 t}\cdot e^{-\lambda_2 t}\cdot\cdots\cdot e^{-\lambda_n t} =e^{\sum_{i=1}^n-\lambda_i t}\tag{8.2}$

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